Transistor as an amplifier

Transistor as an amplifier

  • Main utility of a transistor lies in its ability to amplify weak signals

  • An amplifier is a circuit which is capable of increasing the signals and a transistor can not accomplish this task.
  • Along with transistors an amplifying circuit consists of passive components like resistors and capacitor and a biasing battery
  • We generally use CE configuration of transistor for most of amplifier circuit as it has high current voltage and power gain. Also input and output impedance characterstics of CE type amplifier are suitable for many applications
  • Figure given below shows the basis CE amplifier circuit using an NPN transistor
  • The Battery VBB forward biases the emitter junction and the collector junction is biased by battery VCC relatively higher voltage battery then VBB
    Transistor as an amplifier
  • Role of load resistance RB is to limit the base current within certain specified limits and RC is the load resistance in the collector circuit and amplified AC voltage appears across it.
  • The emitter terminal is common and grounded
  • In this common emitter circuit the input signal is applied to the base and output signal is obtained at the collector
  • We know that very small base current in a transistor corresponds to large collector current

  • Therefore with input signal applied to the base, a very small charge in IB produces a much large change in IC and thus a substantial current gain is obtained
  • The potential difference VBE changes with time due to the alternating input signals and this leads to the change in base current
  • In the absence of ac signal a closed emitter base circuit results IB,IE and IC as base ,emitter and collector currents .From Kirchhoff first law
    IE=IB+IC ----(7)

  • Due to collector current IC a voltage drop develops across RL which is equal to ICRL

  • Applying Kirchhoff�s law in output loop we get
    VCC=VCE+ICRC ---(8)

    and for input loop we get
    VBB=VBE+IBRB ---(9)

  • when input signal vi is not zero then
    VBB+ Vi=VBE+IBRB +ΔIB(RB+ri)
    where ri is the input dynamic resistance relating VBE and IB as given in equation (3).Hence
    The change in IB causes a change in IC. Thus AC current gain Ai (or Βac) is defined as
    Βac=ΔIC/ΔIB=iC/ib ---(10)

  • Change in collector current IC due to change in IB causes a change in VCE and the voltage drop across RC as VCC is fixed

  • Thus from equation (8)
    as ΔVCC=0
    This change in VCE is the output voltage ,Thus
  • Voltage gain for the amplifier is
    Av=v0/vi=ΔVCE/rΔIB=-ΒacRC/r ---(11)
    Here negative sign in equation (11) represents that the phase of the output voltage is opposite to that of input voltage

  • Power gain of the amplifier is given by
    ApacAvac2RC/r ---(12)

Also Read

Latest Updates
Synthetic Fibres and Plastics Class 8 Practice questions

Class 8 science chapter 5 extra questions and Answers

Mass Calculator

3 Fraction calculator

Garbage in Garbage out Extra Questions7