- Introduction
- |
- Position and Displacement
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- Average velocity and speed
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- Instantaneous velocity and speed
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- Acceleration
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- Motion with constant acceleration
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- Free fall acceleration
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- Relative velocity
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- Solved Examples Part 1
- |
- Solved Examples Part 2
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- Solved Examples Part 3
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- Solved Examples Part 4
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- Solved Examples Part 5

- Position Distance and Displacement
- |
- Average velocity and speed
- |
- Velocity and acceleration
- |
- Uniformly accelerated motion
- |
- Relative Velocity
- |
- Kinematics Question 1
- |
- Kinematics Question 2

- Freely falling motion of any body under the effect of gravity is an example of uniformly accelerated motion.

- Kinematic equation of motion under gravity can be obtained by replacing acceleration
**'a'**in equations of motion by acceleration due to gravity**'g'**.

- Value of g is equal to 9.8 m.s
^{-2}.

- Thus kinematic equations of motion under gravity are

v = v_{0}+ gt (16a)

x = v_{0}t + ½ ( gt^{2}) (16b)

v^{2}= (v_{0})^{2}+ 2gx (16c)

- The value of g is taken positive when the body falls vertically downwards and negative when the body is projected up against gravity.

- Consider two objects A and B moving with uniform velocities v
_{A}and v_{B}along two straight and parallel tracks.

- Let x
_{OA}and x_{OB}be their distances from origin at time t=0 and x_{A}and x_{B}be their distances from origin at time t.

- For object A

x_{A}= x_{OA}+ v_{A}t (18)

and for object B

x_{B}= x_{OB}+ v_{B}t (19)

subtracting equation 18 from 19

x_{B}- x_{A}= ( x_{OB}- x_{OA}) + ( v_{B}- v_{A}) t (20)

- Above equation 20 tells that as seen from object A , object B seems to have velocity ( v
_{B}- v_{A}) .

- Thus ( v
_{B}- v_{A}) is the velocity of object B relative to object A. Thus,

v_{BA}= ( v_{B}- v_{A}) (21)

- Similarly velocity of object A relative to object B is

v_{AB}= ( v_{A}- v_{B}) (22)

- If v
_{B}= v_{A}then from equation 20

x_{B}- x_{A}= ( x_{OB}- x_{OA})

i.e., two objects A and B stays apart at constant distance.

- v
_{A}> v_{B}then (v_{B}- v_{A}) would be negative and the distance between two objects will go on decreasing by an amount ( v_{A}- v_{B}) after each unit of time. After some time they will meet and then object A will overtake object B.

- If v
_{A}and v_{B}have opposite signs then magnitude of v_{BA}or v_{AB}would be greater then the magnitude of velocity of A or that of B and objects seems to move very fast.

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