Given below are the Class 10 Maths Problems for Polynomials with solutions
(a) cubic polynomials problems
(b) quadratic polynomials Problems
(c) Word Problems
Question 1 Verify that 3, -1, -1/3 are the zeroes of the cubic polynomial $p(x)=3x^3-5x^2-11x-3$ Solution
Question 2 Verify that -5,1/2,3/4 are zeroes of cubic polynomial $4y^3 + 20y + 2y -3$. Also verify the relationship between the zeroes and the coefficients. Question 3 Using division show that $3x^2 + 5$ is a factor of $6x^5 + 15x^4 + 16x^3 + 4x^2 + 10x - 35$. Solution
Question 4 Using division state whether $2y - 5$ is a factor of $4y^4 - 10y^3 - 10y^2 + 30y - 15$. Solution
So it is not a factor
Question 5 Check whether $g(x) = x^2 - 3$ is a factor of $p(x) = 2x^4 + 3x^3 - 2x^2 - 9x -12$ by applying division algorithm. Solution
Question 6 Check whether $p(x) = x^2 +3x +1$ is a factor of $g(x) = 3x^4+ 5x^3 - 7x^2+ 2x + 2$ by using division algorithm. Solution
Question 7 Find remainder when $x^3 - bx^2 + 5- 2b$ is divided by $x - b$. Solution
Given $p(x) =x^3 - bx^2 + 5- 2b$
By remainder theorem
$p(b) = b^3-b^3+5-2b= 5-2b$
Question 8 Check whether polynomial $x - 3$ is a factor of the polynomial $x^3 - 3x^2 - x + 3$. Verify by division algorithm. Solution
Question 9 If $4x^4 + 7x^3 - 4x^2 - 7x + p$ is completely divisible by $x^3 - x$, then find the value of p. Solution
Let $q(x) =4x^4 + 7x^3 - 4x^2 - 7x + p$
$x^3 - x$
$=x(x-1)(x+1)$
So x=0 is a factor of q(x)
$q(0) = 0 + 0 -0 -0 + p =0$
or p=0
Question 10 If α and β are the zeroes of the quadratic polynomial $f(x) = kx^2 + 4x + 4$ such that α2 + β2 = 24, find the values of k. Solution
for $f(x) = kx^2 + 4x + 4$
α + β=-4/k
αβ=4/k
Now α2 + β2 = 24
(α + β)2 � 2αβ = 24
16/k2 -8/k =24
or
3k2+k-2=0
or k=-1 or 2/3
Question 11 If α and β are the zeroes of the quadratic polynomial $f(x) = 2x^2 - 5x + 7$, find a polynomial whose zeroes are 2α + 3β and 3α + 2β. Solution
for $f(x) = 2x^2 - 5x + 7$
α + β=5/2
αβ=7/2
Now sum of new zeroes
2α + 3β+3α + 2β=5(α + β)=25/2
Product of Zeroes
(2α + 3β)(3α + 2β)=6(α2 + β2) +13αβ
=6(α + β)2 +αβ=157/2
Now required Quadratic Polynomial
g(x) = x2 -(Sum of Zeroes)x +(Product of Zeroes)
=x2 – (25/2)x + (157/2)
=2x2 – 25x + 157
Question 12 If the squared difference of the zeroes of the quadratic polynomial
$f(x) = x^2 + px + 45$ is equal to 144, find the value of p. Solution
Let α,β are the roots of the quadratic polynomial $f(x) = x^2 + px + 45$ then
&alpha + β = -p and αβ = 45
Given (α - β)2 = 144
or (α + β)2 � 4αβ = 144
(�p)2 � 4 � 45 = 144
p 2 � 180 = 144
p2 = 144 + 180 = 324
Thus, the value of p is +18 or -18
Question 13 If α and β are the zeroes of the quadratic polynomial $f(x) = x^2 - p (x + 1) - c$, show that (α + 1) (β + 1) = 1 – c. Solution
Question 14 What must be subtracted from the polynomial $f(x) = x^4 + 2x^3 - 13x^2- 12x + 21$
so that the resulting polynomial is exactly divisible by $x^2 - 4x + 3$? Solution
Using division algorithm
$2x-3$ should be subtracted from polynomial $f(x) = x^4 + 2x^3 - 13x^2- 12x + 21$
Question 15 Verify that 1, 2 and -1/2 are zeroes of $2x^3 - 5x^2 + x + 2$. Also verify the relationship between the zeroes and the coefficients. Question 16 On dividing the polynomial $4x^4 - 5x^3 - 39x^2 -46x- 2$ by the polynomial g(x), the quotient is $x^2 - 3x -5$ and the remainder is $-5x + 8$. Find the polynomial g(x). Solution
Now required Quadratic Polynomial
g(x) = x2 -(Sum of Zeroes)x +(Product of Zeroes)
=x2 -p2x +(p2)(p2 -4q)
=x2 -p2x +p4-4qp2
Summary
This Class 10 Maths Problems for Polynomials with answers is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feedback on the mail.
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