In this page we have *Practice Questions for Linear equations Class 8 maths Chapter 2* . Hope you like them and do not forget to like , social share
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(a) $x + 2 = -11$

(b) $2x - \frac {1}{6} = 3$

(c) $7x - 7 = 21$

(d) $-7x = 84$

(e) $18 +7x = -3$

(f) $3(x - 4) = 21$

(g)$ \frac {3x}{2} - \frac {2x}{3} = 8$

(h) $3x - 9 = 4x - 3$

(i) $3(2x - 3) = 4(2x + 4)$

a. x=-13

b. x= 19/12

c. x=4

d. x=-12

e. x=-3

f. x= 11

g. x= 48/5

h. x=-6

i. x=-25/2

(a) $\frac {x}{2} - 10 = \frac {1}{2}$

(b) $ \frac {x}{3} - \frac {x}{2} = 6$

(c) $6x - 9 - 2(1 + x) = x - 9$

(d) $2(x +2) + 5(x + 5) = 4(x - 8) + 2(x - 2)$

(e) $\frac {3 + y}{y + 7)} = \frac {3}{5}$

(f) $ \frac {3x - 2}{2x - 3} = - \frac {1}{2}$

(g) (x - 7 )/3 = (x - 1)/5

a. x=21

b. x=-36

c. x= 2/3

d. x=-63

e. y=3

f. x= 7/8

g. x=16

A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers become twice of another new numbers. Find the original numbers.

The sum of three consecutive multiples of 8 is 888. Find the multiple.

Let the three consecutive multiple of 8 be 8x ,8(x+1) , 8(x+2)

Now

$8x + 8(x+1) + 8(x+2)=888$

$8x + 8x + 8 + 8x + 16 =888$

$24x + 24 =888$

$24x = 864$

x=36

So multiples are 36,37 and 38

This Practice Questions for Linear equations Class 8 maths Chapter 2 is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feedback on the mail.

**Notes****Worksheets****Ncert Solutions**- class 8 maths chapter 2 exercise 2.1 solutions
- class 8 maths chapter 2 exercise 2.2 solutions
- NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.3
- NCERT Solutions for Linear equations Class 8 maths Chapter 2 Exercise 2.4
- class 8 maths chapter 2 exercise 2.5 solutions
- class 8 maths chapter 2 exercise 2.6 solutions

Class 8 Maths Class 8 Science