# Practice Questions for Linear equations Class 8 maths Chapter 2

In this page we have Practice Questions for Linear equations Class 8 maths Chapter 2 . Hope you like them and do not forget to like , social share and comment at the end of the page.
Question 1
Solve each of the following equations
(a) $x + 2 = -11$
(b) $2x - \frac {1}{6} = 3$
(c) $7x - 7 = 21$
(d) $-7x = 84$
(e) $18 +7x = -3$
(f) $3(x - 4) = 21$
(g)$\frac {3x}{2} - \frac {2x}{3} = 8$
(h) $3x - 9 = 4x - 3$
(i) $3(2x - 3) = 4(2x + 4)$

a. x=-13
b. x= 19/12
c. x=4
d. x=-12
e. x=-3
f. x= 11
g. x= 48/5
h. x=-6
i. x=-25/2

Question 2
Solve each of the following equations and check your solution by substituting in the equation.
(a) $\frac {x}{2} - 10 = \frac {1}{2}$
(b) $\frac {x}{3} - \frac {x}{2} = 6$
(c) $6x - 9 - 2(1 + x) = x - 9$
(d) $2(x +2) + 5(x + 5) = 4(x - 8) + 2(x - 2)$
(e) $\frac {3 + y}{y + 7)} = \frac {3}{5}$
(f) $\frac {3x - 2}{2x - 3} = - \frac {1}{2}$
(g) (x - 7 )/3 = (x - 1)/5

a. x=21
b. x=-36
c. x= 2/3
d. x=-63
e. y=3
f. x= 7/8
g. x=16

Question 3
A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers become twice of another new numbers. Find the original numbers.
Question 4
The sum of three consecutive multiples of 8 is 888. Find the multiple.

Let the three consecutive multiple of 8 be 8x ,8(x+1) , 8(x+2)
Now
$8x + 8(x+1) + 8(x+2)=888$
$8x + 8x + 8 + 8x + 16 =888$
$24x + 24 =888$
$24x = 864$
x=36
So multiples are 36,37 and 38

## Summary

This Practice Questions for Linear equations Class 8 maths Chapter 2 is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feedback on the mail.