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Solve the following linear equations

- $11 x + 10 = 10 x + 6$
- $12 x + 5 = 5 x + 3$
- $16 x + 9 = 9 x + 5$
- $11 x + 2 = 2 x + 10$
- $18 x + 4 = 4 x + 8$
- $20 x + 10 = 10 x + 4$
- $9 x + 6 = 6 x + 3$
- $9 x + 3 = 3 x + 10$

Answers

- $\frac{3 x + 8}{9 x + 4} = \frac{3}{8}$
- $\frac{6 x + 3}{7 x + 4} = 2$
- $\frac{7 x + 3}{9 x + 5} = \frac{7}{3}$
- $\frac{5 x + 4}{10 x + 10} = \frac{5}{4}$
- $\frac{6 x + 7}{x + 6} = \frac{6}{7}$
- $\frac{x + 4}{2 x + 4} = \frac{1}{4}$

Answers

- $\frac{x}{8} + 6 = \frac{x}{6} + 2$
- $\frac{x}{10} + 4 = \frac{x}{9} + 8$
- $\frac{x}{10} + 6 = \frac{x}{3} + 8$
- $\frac{x}{3} + 10 = \frac{x}{10} + 7$
- $x + 5 = \frac{x}{8} + 9$
- $\frac{x}{4} + 1 = \frac{x}{9} + 2$
- $\frac{x}{8} + 9 = \frac{x}{10} + 6$
- $\frac{x}{10} + 7 = \frac{x}{2} + 9$

Solution

(a) $\frac {x+1}{4} = \frac {x-2}{2}$

(b) $1 -(p - 2) - [(p - 3) - (p - 1)] = 0$

(c) $7x - 7 = 21 -5x$

(d) $-7x = 84 +x$

(e)$0.25 (4m - 5) = 0.75m + 8$

(f) $3(x - 4) = 21$

(g)$\frac {3x}{2} - \frac {x}{3} = 8$

(h) $ \frac {y}{2} -\frac {1}{4}(y- \frac {1}{3}) = \frac {1}{6} (y+1) + \frac {1}{12}$

(i) 3(2z - 3) = 12(2z + 4)

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The sum of three consecutive odd natural numbers is 69. Find the prime number out of these numbers

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A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers become twice of another new numbers. Find the original numbers.

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The shifting of a number from one side of an equation to other is called

(a) Transposition

(b) Distributivity

(c) Commutativity

(d) Associativity

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1. Shifting of variable or constant from one side to another side

5. A statement formed when an equal sign in placed between two expressions.

7. The value of x for 2x -4=10

2. The values for which the equation LHS equals RHS

3. If a term of an expression consists of a number multiplied by one or more variables, this number is the __________________ of the term

4. highest power of the variable in linear equation

6. Branch of mathematics concerned with operation by symbolic numbers

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This Test Paper for Linear equations Class 8 maths Chapter 2 is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feebback on the mail.

**Notes****Worksheets****Ncert Solutions**- NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.1
- NCERT Solutions for Linear equations Class 8 maths Chapter 2 Exercise 2.2
- class 8 maths chapter 2 exercise 2.3 solutions
- class 8 maths chapter 2 exercise 2.4 solutions
- class 8 maths chapter 2 exercise 2.5 solutions
- class 8 maths chapter 2 exercise 2.6 solutions

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