physicscatalyst.com logo





NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2 Exercise 2.3




In this page we have NCERT Solutions for Linear equations Class 8 Mathematics for Exercise 2.3 . Hope you like them and do not forget to like , social share and comment at the end of the page.

NCERT Solutions for Linear equations Class 8 Maths Chapter 2 Exercise 2.3

Solving Equations having the Variable on both Sides
Tips for this NCERT Exercise
(1) Validation or check result means to verify the answer by putting the values in the linear equation
(2) Calculate the LHS(Left Hand side) by substituting the variable and similary calculate the RHS(Right hand side) by substituting the variable
(3) Both the LHS and RHS should be equal
Question 1
Solve and check result: $3x= 2x+ 18$
Answer
$3x= 2x+ 18$
Transposing 2x to L.H.S, we obtain
$3x- 2x= 18$
x= 18
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 3x= 3 × 18 = 54
R.H.S = 2x+ 18 = 2 × 18 + 18 = 36 + 18 = 54
L.H.S. = R.H.S.
It proves that result is correct

Question 2
Solve and check result: $5t- 3 = 3t- 5$
Answer
$5t- 3 = 3t- 5$
Transposing 3t to L.H.S and -3 to R.H.S, we obtain
$5t- 3t= -5 - (-3)$
2t= -2
Dividing both sides by 2
t= -1
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 5t- 3 = 5 × (-1) - 3 = -8
R.H.S = 3t- 5 = 3 × (-1) - 5 = - 3 - 5 = -8
L.H.S. = R.H.S.
It proves that result is correct

Question 3
Solve and check result
$5x+ 9 = 5 + 3x$
Answer
$5x+ 9 = 5 + 3x$
Transposing 3x to L.H.S and 9 to R.H.S, we obtain
$5x- 3x= 5 - 9$
2x= -4
Dividing both sides by 2, we obtain
x= -2
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 5x+ 9 = 5 × (-2) + 9 = -1
R.H.S = 5 + 3x= 5 + 3 × (-2) = -1
L.H.S. = R.H.S.
It proves that result is correct

Question 4
Solve and check result:
$4z+ 3 = 6 + 2z$
Answer
$4z+ 3 = 6 + 2z$
Transposing 2z to L.H.S and 3 to R.H.S, we obtain
$4z- 2z= 6 - 3$
2z= 3
Dividing both sides by 2, we obtain
z=3/2
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 4z+ 3 = 4 × (3/2)+ 3 = 6 + 3 = 9
R.H.S = 6 + 2z= 6 + 2 × (3/2)= 6 + 3 = 9
L.H.S. = R.H.S.
It proves that result is correct

Question 5
Solve and check result:
$2x- 1 = 14 -x$
Answer
$2x- 1 = 14 -x$
Transposing x to L.H.S and 1 to R.H.S, we obtain
$2x+x= 14 + 1$
3x= 15
Dividing both sides by 3, we obtain
x= 5
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 2x- 1 = 2 × (5) - 1 = 10 - 1 = 9
R.H.S = 14 -x= 14 - 5 = 9
L.H.S. = R.H.S.
It proves that result is correct




Question 6
Solve and check result:
$8x+ 4 = 3(x- 1) + 7$
Answer
$8x+ 4 = 3(x- 1) + 7$
$8x+ 4 = 3x- 3 + 7$
Transposing 3x to L.H.S and 4 to R.H.S, we obtain
$8x- 3x= - 3 + 7 - 4$
$5x= - 7 + 7$
5x=0
x=0
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 8x+ 4 = 8 × (0) + 4 = 4
R.H.S = 3(x- 1) + 7 = 3 (0 - 1) + 7 = - 3 + 7 = 4
L.H.S. = R.H.S.
It proves that result is correct

Question 7-
Solve and check result: NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2
Answer
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2
Multiplying both sides by 5, we obtain
$5x= 4(x+ 10)$
$5x= 4x+ 40$
Transposing 4x to L.H.S, we obtain
5x- 4x= 40
x= 40
Let us evaluate both the LHS and RHS for validate the answer
L.H.S =x= 40
R.H.S = NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2=40
L.H.S. = R.H.S.
It proves that result is correct

Question 8
Solve and check result: NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2 Exercise 2.3
Answer
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2 Exercise 2.3
Transposing 7x/15 on LHS and 1 on RHS
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2 Exercise 2.3
Multiplying by 15 on both sides
10x-7x= 30
3x=30
Dividing by 3 on both the sides
x=10
Let us evaluate both the LHS and RHS for validate the answer
L.H.S =NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2 Exercise 2.3 =23/3
R.H.S=NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2 Exercise 2.3 =23/3
L.H.S. = R.H.S.
It proves that result is correct

Question 9
Solve and check result
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2 Exercise 2.3
Answer
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2
Transposingyto L.H.S and5/3 to R.H.S, we obtain
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2
3y=21/3
3y=7
Dividing both sides by 3, we obtain
y=7/3
Let us evaluate both the LHS and RHS for validate the answer
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2
L.H.S. = R.H.S.
It proves that result is correct

Question 10
Solve and check result:
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2
Answer
NCERT Solutions for Linear equations Class 8 Mathematics Chapter 2
Transposing 3m to R.H.S and 8/5 to L.H.S
8/5= 2m
Dividing both sides by 2
m=4/5
Let us evaluate both the LHS and RHS for validate the answer
L.H.S =3m=12/5
R.H.S =5m –(8/5)=12/5
L.H.S. = R.H.S.
It proves that result is correct

Practice similar type questions

(1) Solve and check the result for $4n +7 = 23$
(2) Solve and check the result $3x - 4 = 1 - 2 x$
(3) Solve and check the result $ \frac {m}{2} -11= 2$
(4) Solve and check the result $ 11y =6y - \frac {1}{3}$
(5) Solve the check the result $ \frac {x}{5} + 8=30$

Download Linear equation Exercise 2.3 as pdf
link to this page by copying the following text
Also Read





Class 8 Maths Class 8 Science