In this page we have class 8 maths chapter 2 exercise 2.1 solutions .This exercise has questions about simple linear equation where we have linear expression on Present on both the left and right side of the equation. Hope you like them and do not forget to like , social share
and comment at the end of the page.
Tips for this NCERT Exercise
(1) Validation or check result means to verify the answer by putting the values in the linear equation
(2) Calculate the LHS(Left Hand side) by substituting the variable and similary calculate the RHS(Right hand side) by substituting the variable
(3) Both the LHS and RHS should be equal
Class 8 maths chapter 2 exercise 2.3 solutions
Question 1
Solve and check result: $3x= 2x+ 18$ Answer
$3x= 2x+ 18$
Transposing 2x to L.H.S, we obtain
$3x- 2x= 18$
x= 18
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 3x= 3 × 18 = 54
R.H.S = 2x+ 18 = 2 × 18 + 18 = 36 + 18 = 54
L.H.S. = R.H.S.
It proves that result is correct
Question 2
Solve and check result: $5t- 3 = 3t- 5$ Answer
$5t- 3 = 3t- 5$
Transposing 3t to L.H.S and -3 to R.H.S, we obtain
$5t- 3t= -5 - (-3)$
2t= -2
Dividing both sides by 2
t= -1
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 5t- 3 = 5 × (-1) - 3 = -8
R.H.S = 3t- 5 = 3 × (-1) - 5 = - 3 - 5 = -8
L.H.S. = R.H.S.
It proves that result is correct
Question 3
Solve and check result
$5x+ 9 = 5 + 3x$ Answer
$5x+ 9 = 5 + 3x$
Transposing 3x to L.H.S and 9 to R.H.S, we obtain
$5x- 3x= 5 - 9$
2x= -4
Dividing both sides by 2, we obtain
x= -2
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 5x+ 9 = 5 × (-2) + 9 = -1
R.H.S = 5 + 3x= 5 + 3 × (-2) = -1
L.H.S. = R.H.S.
It proves that result is correct
Question 4
Solve and check result:
$4z+ 3 = 6 + 2z$ Answer
$4z+ 3 = 6 + 2z$
Transposing 2z to L.H.S and 3 to R.H.S, we obtain
$4z- 2z= 6 - 3$
2z= 3
Dividing both sides by 2, we obtain
z=3/2
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 4z+ 3 = 4 × (3/2)+ 3 = 6 + 3 = 9
R.H.S = 6 + 2z= 6 + 2 × (3/2)= 6 + 3 = 9
L.H.S. = R.H.S.
It proves that result is correct
Question 5
Solve and check result:
$2x- 1 = 14 -x$ Answer
$2x- 1 = 14 -x$
Transposing x to L.H.S and 1 to R.H.S, we obtain
$2x+x= 14 + 1$
3x= 15
Dividing both sides by 3, we obtain
x= 5
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 2x- 1 = 2 × (5) - 1 = 10 - 1 = 9
R.H.S = 14 -x= 14 - 5 = 9
L.H.S. = R.H.S.
It proves that result is correct
Question 6
Solve and check result:
$8x+ 4 = 3(x- 1) + 7$ Answer
$8x+ 4 = 3(x- 1) + 7$
$8x+ 4 = 3x- 3 + 7$
Transposing 3x to L.H.S and 4 to R.H.S, we obtain
$8x- 3x= - 3 + 7 - 4$
$5x= - 7 + 7$
5x=0
x=0
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = 8x+ 4 = 8 × (0) + 4 = 4
R.H.S = 3(x- 1) + 7 = 3 (0 - 1) + 7 = - 3 + 7 = 4
L.H.S. = R.H.S.
It proves that result is correct
Question 7-
Solve and check result:
Answer
Multiplying both sides by 5, we obtain
$5x= 4(x+ 10)$
$5x= 4x+ 40$
Transposing 4x to L.H.S, we obtain
5x- 4x= 40
x= 40
Let us evaluate both the LHS and RHS for validate the answer
L.H.S =x= 40
R.H.S = =40
L.H.S. = R.H.S.
It proves that result is correct
Question 8
Solve and check result:
Answer
Transposing 7x/15 on LHS and 1 on RHS
Multiplying by 15 on both sides
10x-7x= 30
3x=30
Dividing by 3 on both the sides
x=10
Let us evaluate both the LHS and RHS for validate the answer
L.H.S = =23/3
R.H.S= =23/3
L.H.S. = R.H.S.
It proves that result is correct
Question 9
Solve and check result Answer
Transposingyto L.H.S and5/3 to R.H.S, we obtain
3y=21/3
3y=7
Dividing both sides by 3, we obtain
y=7/3
Let us evaluate both the LHS and RHS for validate the answer
L.H.S. = R.H.S.
It proves that result is correct
Question 10
Solve and check result: Answer
Transposing 3m to R.H.S and 8/5 to L.H.S
8/5= 2m
Dividing both sides by 2
m=4/5
Let us evaluate both the LHS and RHS for validate the answer
L.H.S =3m=12/5
R.H.S =5m –(8/5)=12/5
L.H.S. = R.H.S.
It proves that result is correct
Practice similar type questions
(1) Solve and check the result for $4n +7 = 23$
(2) Solve and check the result $3x - 4 = 1 - 2 x$
(3) Solve and check the result $ \frac {m}{2} -11= 2$
(4) Solve and check the result $ 11y =6y - \frac {1}{3}$
(5) Solve the check the result $ \frac {x}{5} + 8=30$
Summary
NCERT Solutions for Linear equations Class 8 maths Chapter 2 Exercise 2.1 has been prepared by Expert with utmost care. If you find any mistake.Please do provide feedback on mail. You can download the solutions as PDF in the below Link also Download class 8 maths chapter 2 exercise 2.1 solutions as pdf
This chapter 2 has total 2 Exercise 2.1,2.2. Exercise 2.3,2.4,2.5.2.6 has been deleted as per latest syllabus. This is the First exercise in the chapter.You can explore previous exercise of this chapter by clicking the link below
=23/3
=23/3
