- What is algebraic expression
- |
- What is algebraic equation
- |
- What is Linear equation in one Variable
- |
- Solving Equations which have Linear Expressions on one Side and Numbers on the other Side
- |
- Word Problem
- |
- Solving Equations having the Variable on both Sides
- |
- Reducing Equations to Simpler Form
- |
- Equations Reducible to the Linear Form

In this page we have *NCERT book Solutions for Class 8th Maths:Linear equations Chapter 2 * for
Exercise 2.5 . Hope you like them and do not forget to like , social share
and comment at the end of the page.

L.C.M. of the denominators, 2, 3, 4, and 5, is 60.

So Multiplying both sides by 60, we obtain

30

Transposing 20x to R.H.S and 12 to L.H.S, we obtain

30

10

X=27/10=2.7

L.C.M. of the denominators, 2, 4, and 6, is 12.

Multiplying both sides by 12, we obtain

6

7

Dividing by 7 on both the sides

n=36

L.C.M. of the denominators, 2, 3, and 6, is 6.

Multiplying both sides by 6, we obtain

6

6

5

Dividing by 5 on both the sides

x=-5

L.C.M. of the denominators, 3 and 5, is 15.

Multiplying both sides by 15, we obtain

5(

5

5

2

Dividing both the sides by 2

x=8

L.C.M. of the denominators, 3 and 4, is 12.

Multiplying both sides by 12, we obtain

3(3

9

9

13

Dividing by 13 on both the sides

t=2

L.C.M. of the denominators, 2 and 3, is 6.

Multiplying both sides by 6, we obtain

6

6

6

5

Dividing by 5 on both the sides

m=7/5

3(

3

−9 − 5 = 10

−14 = 7t

t=-2

15(

15

18

18

3(5

3(5

15

−3

−3

−35

z=2

0.25(4

Multiplying both sides by 20, we obtain

5(4

20

20

10

f==6/10=3/5

Download NCERT Solutions Exercise 2.5 as pdf

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