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In this page we have Linear equation problems with answers . Hope you like them and do not forget to like , social share
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Solve the below linear equation problems
- $\frac{1}{z + 10} = \frac{2}{z - 4}$
- $\frac{1}{z + 4} = \frac{2}{z - 4}$
- $\frac{1}{z + 5} = \frac{2}{z - 3}$
- $\frac{z}{3} = \frac{z}{9} - \frac{8}{9}$
- $\frac{x}{3} + 1 = \frac{x}{10} + 9$
- $2(x-1) +3(x-2) +4(x-3) = 16$
- $\frac{1}{z + 8} = \frac{2}{z - 7}$
- $\frac{z}{6} = \frac{z}{8} - \frac{5}{8}$
- $\frac{x}{6} + 2 = \frac{x}{10} + 10$
- $\frac{4 x + 10}{7 x + 8} = \frac{2}{5}$
- $ 10x + 3 =12 +2x$
- $\frac{1}{z + 9} = \frac{2}{z - 10}$
- $\frac{1}{q + 7} = \frac{2}{q - 8}$
- $\frac{y}{5} = \frac{y}{10} - \frac{1}{10}$
- $x + 1 = \frac{x}{6} + 7$
- $\frac{1}{z + 4} = \frac{2}{z - 9}$
- $\frac{x}{3} + 9 = \frac{x}{6} + 5$
- $\frac{1}{z + 8} = \frac{2}{z - 1}$
- $\frac{1}{z + 9} = \frac{2}{z - 3}$
- $\frac{1}{z + 4} = \frac{2}{z - 2}$
- $\frac{7 x + 1}{5 x + 5} = 7$
- $\frac{1}{z + 9} = \frac{2}{z - 1}$
- $x + 7 = \frac{x}{10} + 7$
- $\frac{x + 5}{4 x + 3} = \frac{1}{5}$
- $\frac{2 x + 3}{5 x + 3} = \frac{2}{3}$
- $ x+1 = 2x+ 6$
- $(x-1)(x-2) =(x+3)(x+4)$
- $\frac{5 x + 1}{8 x + 1} = 5$
- $\frac{1}{z + 5} = \frac{2}{z - 1}$
Answers
- $z = -24$
- $z = -12$
- $z = -13$
- $z = -4$
- $x = \frac{240}{7}$
- $x=4$
- $z = -23$
- $z = -15$
- $x = 120$
- $x = - \frac{17}{3}$
- $x=1$
- $z = -28$
- $q = -22$
- $y = -1$
- $x = \frac{36}{5}$
- $z = -17$
- $x = -24$
- $z = -17$
- $z = -21$
- $z = -10$
- $x = - \frac{17}{14}$
- $z = -19$
- $x = 0$
- $x = -22$
- $x = \frac{3}{4}$
- $x=-5$
- $x=-1$
- $x = - \frac{4}{35}$
- $z = -11$
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