In this page we have *NCERT Solutions for Class 8 Maths Chapter 2.3 Linear equations in One Variable * for
Exercise 2.3.This exercise has questions about simple linear equation where we have linear expression on one side and Numbers on Other side .the Hope you like them and do not forget to like , social share
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Solving Equations which have Linear Expressions on one Side and Numbers on the other Side

Solve: x-2=7

Transposing 2 to R.H.S, we obtain

Solve: y+3=10

Transposing 3 to R.H.S, we obtain

Solve: 6=z+2

6=z+2

Or

z+2=6

Transposing 2 to R.H.S, we obtain

z=6 -2=4

Solve:

$\frac {3}{7} + x =\frac {17}{7}$

$\frac {3}{7} + x =\frac {17}{7}$

Transposing 3 to R.H.S, we obtain

7x=17-3=14

7x=14

Dividing both the sides by 7

x=2

Solve:

6x=12

6x=12

Dividing both the sides by 6

x=2

Solve:

$\frac {t}{5}=10$

$\frac {t}{5}=10$

Multiplying 5 on both sides

t=50

Solve

$\frac {2x}{3}=18$

$\frac {2x}{3}=18$

Multiplying both the sides by 3

2x=54

Dividing both the sides by 2

x=27

Solve:

$1.6 = \frac {y}{1.5}$

$1.6 = \frac {y}{1.5}$

Multiplying both the sides by 1.5

1.6 × 1.5=y

y=2.4

Solve:

7x-9=16

7x-9=16

Transposing 9 to R.H.S, we obtain

7x=16+9

7x=25

Dividing by 7 on both the sides

x=25/7

Solve:

14y-8=13

14y-8=13

Transposing 8 to R.H.S, we obtain

14y=13+8

14y=21

Dividing 14 on both the sides

y=21/14=3/2

Solve:

17+6p=9

17+6p=9

Transposing 17 to R.H.S, we obtain

6p=9-17

6p=-8

Dividing 6 on both the sides

p=-8/6=-4/3

Solve:

$\frac {x}{3}+1=\frac {7}{15}$

$\frac {x}{3}+1=\frac {7}{15}$

The LCM of denominator is 15, So multiplying both sides by 15

5x +15=7

Transposing 15 to R.H.S, we obtain

5x=-8

Dividing 5 on both the sides

x=-8/5

- NCERT Solutions for Class 8 Maths Chapter 2 Linear equations in One Variable Exercise 2.2 has been prepared by Expert with utmost care. If you find any mistake.Please do provide feedback on mail. You can download the solutions as PDF in the below Link also

Download NCERT solution linear equation Exercise 2.2 as pdf - This chapter 2 has total 6 Exercise 2.1,2.2. Exercise 2.3,2.4,2.5.2.6 has been deleted as part of latest syllabus. This is one of the deleted exercise in the chapter.You can explore previous exercise of this chapter by clicking the link below

**Notes****Worksheets****Ncert Solutions**- class 8 maths chapter 2 exercise 2.1 solutions
- class 8 maths chapter 2 exercise 2.2 solutions
- NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.3
- NCERT Solutions for Linear equations Class 8 maths Chapter 2 Exercise 2.4
- class 8 maths chapter 2 exercise 2.5 solutions
- class 8 maths chapter 2 exercise 2.6 solutions

Class 8 Maths Class 8 Science