## Linear equations in One Variable Chapter 2 Exercise 2.1

In this page we have *NCERT Solutions for Class 8 Maths Chapter 2 : Linear equations in One Variable * for
Exercise 2.1. Hope you like them and do not forget to like , social share
and comment at the end of the page.

Solving Equations which have Linear Expressions on one Side and Numbers on the other Side

**Question 1:**
**Solve: x-2=7**
**Answer:**
*x* - 2 = 7

Transposing 2 to R.H.S, we obtain

*x* = 7 + 2 = 9

**Question 2:**
**Solve: y+3=10**
**Answer :**
*y* + 3 = 10

Transposing 3 to R.H.S, we obtain

*y* = 10 - 3 = 7

**Question 3:**
**Solve: 6=z+2**
**Answer**
**6=z+2**
Or

z+2=6

Transposing 2 to R.H.S, we obtain

z=6 -2=4

**Question 4**
**Solve: **
$\frac {3}{7} + x =\frac {17}{7}$

**Answer :**
$\frac {3}{7} + x =\frac {17}{7}$

**Multiplying 7 on both sides**
**3+7x=17**
Transposing 3 to R.H.S, we obtain

7x=17-3=14

7x=14

Dividing both the sides by 7

x=2

**Question 5:**
**Solve: **
6x=12

**Answer:**
6x=12

Dividing both the sides by 6

x=2

**Question 6:**
**Solve: **
$\frac {t}{5}=10$

**Answer:**
$\frac {t}{5}=10$

Multiplying 5 on both sides

t=50

**Question 7:**
**Solve**
$\frac {2x}{3}=18$

**Answer:**
$\frac {2x}{3}=18$

Multiplying both the sides by 3

2x=54

Dividing both the sides by 2

x=27

**Question 8:**
**Solve: **
$1.6 = \frac {y}{1.5}$

**Answer:**
$1.6 = \frac {y}{1.5}$

Multiplying both the sides by 1.5

1.6 × 1.5=y

y=2.4

**Question 9:**
Solve:

7x-9=16

**Answer:**
7x-9=16

Transposing 9 to R.H.S, we obtain

7x=16+9

7x=25

Dividing by 7 on both the sides

x=25/7

**Question 10:**
Solve:

14y-8=13

**Answer:**
14y-8=13

Transposing 8 to R.H.S, we obtain

14y=13+8

14y=21

Dividing 14 on both the sides

y=21/14=3/2

**Question 11:**
Solve:

17+6p=9

**Answer:**
17+6p=9

Transposing 17 to R.H.S, we obtain

6p=9-17

6p=-8

Dividing 6 on both the sides

p=-8/6=-4/3

**Question 12:**
**Solve: **
$\frac {x}{3}+1=\frac {7}{15}$

**Answer:**
$\frac {x}{3}+1=\frac {7}{15}$

The LCM of denominator is 15, So multiplying both sides by 15

**5x +15=7**
Transposing 15 to R.H.S, we obtain

5x=-8

Dividing 5 on both the sides

x=-8/5

Download NCERT solution linear equation Exercise 2.1 as pdf

**link to this page by copying the following text**
**Also Read**

**Notes**
**Worksheets**
**Ncert Solutions**

### Search Our Website

Class 8 Maths
Class 8 Science